(x^3+6x-20)/(x-2)

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Solution for (x^3+6x-20)/(x-2) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(x^3+6*x-20)/(x-2) = 0

x^3+6*x-20 = 0

x^3+6*x-20 = 0

{ 1, -1, 2, -2, 4, -4, 5, -5, 10, -10, 20, -20 }

1

x = 1

x^3+6*x-20 = -13

1

-1

x = -1

x^3+6*x-20 = -27

-1

2

x = 2

x^3+6*x-20 = 0

2

x-2

x^2+2*x+10

x^3+6*x-20

x-2

2*x^2-x^3

2*x^2+6*x-20

4*x-2*x^2

10*x-20

20-10*x

0

x^2+2*x+10 = 0

DELTA = 2^2-(1*4*10)

DELTA = -36

DELTA < 0

x in { 2} 

x-2 = 0

1 = 0

x belongs to the empty set

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